Chemistry Guru - Chemistry Tuition | JC, A Level, H2 Chemistry Tuition Strong Oxidation, Oxidative Cleavage of Alkenes

In this video we want to discuss the strong oxidation or oxidative cleavage of alkenes with KMnO4, dilute H2SO4, heat.

On strong oxidation the C=C double bond will break and what each carbon is converted to depends on the groups that are attached to that carbon.

Let's take a look at the possibilities:

[products of oxidation of alkene]

For alkene carbon bonded to 2 R groups, it'll be oxidised to ketone.

For alkene carbon bonded to 1 R group and 1 H, it'll be oxidised to acid.

For alkene carbon bonded to 2 H, it'll be oxidised to carbon dioxide and water.

Let's have 2 examples. Take a look at the first one.

[example 1]

Carbon 1 is attached to 2 H, so it'll be oxidised to carbon dioxide and water.

Carbon 2 is attached to 1 methyl group and 1 H, so it'll be oxidised to acid.

We can then write down the products:

[example 1 products]

Here's another example.

[example 2]

Carbon 2 is attached to 2 methyl groups so it'll be oxidised to ketone.

Carbon 3 is attached to 1 ethyl group and 1 H, so it'll be oxidised to acid.

Hence we can determine the products for this oxidation:

[example 2 products]

For the detailed step-by-step discussion on how to determine products for strong oxidation of alkenes, check out this video!

Topic: Alkenes, Organic Chemistry, A Level Chemistry, Singapore

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Strong Oxidation, Oxidative Cleavage of Alkenes
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Education	Upload TimePublished on 8 Oct 2018